Optimal. Leaf size=116 \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{5 a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \csc (c+d x)}{d}-\frac{17 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{2 a^2 \log (\sin (c+d x))}{d}+\frac{a^2 \log (\sin (c+d x)+1)}{8 d} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.141646, antiderivative size = 116, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {2836, 12, 88} \[ \frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{5 a^3}{4 d (a-a \sin (c+d x))}-\frac{a^2 \csc (c+d x)}{d}-\frac{17 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{2 a^2 \log (\sin (c+d x))}{d}+\frac{a^2 \log (\sin (c+d x)+1)}{8 d} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \csc ^2(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x))^2 \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{a^2}{(a-x)^3 x^2 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \frac{1}{(a-x)^3 x^2 (a+x)} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^7 \operatorname{Subst}\left (\int \left (\frac{1}{2 a^3 (a-x)^3}+\frac{5}{4 a^4 (a-x)^2}+\frac{17}{8 a^5 (a-x)}+\frac{1}{a^4 x^2}+\frac{2}{a^5 x}+\frac{1}{8 a^5 (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{a^2 \csc (c+d x)}{d}-\frac{17 a^2 \log (1-\sin (c+d x))}{8 d}+\frac{2 a^2 \log (\sin (c+d x))}{d}+\frac{a^2 \log (1+\sin (c+d x))}{8 d}+\frac{a^4}{4 d (a-a \sin (c+d x))^2}+\frac{5 a^3}{4 d (a-a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 0.262242, size = 74, normalized size = 0.64 \[ \frac{a^2 \left (-\frac{10}{\sin (c+d x)-1}+\frac{2}{(\sin (c+d x)-1)^2}-8 \csc (c+d x)-17 \log (1-\sin (c+d x))+16 \log (\sin (c+d x))+\log (\sin (c+d x)+1)\right )}{8 d} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.128, size = 176, normalized size = 1.5 \begin{align*}{\frac{{a}^{2}\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{3}}{4\,d}}+{\frac{3\,{a}^{2}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+{\frac{9\,{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{4\,d}}+{\frac{{a}^{2}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{a}^{2}}{d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+2\,{\frac{{a}^{2}\ln \left ( \tan \left ( dx+c \right ) \right ) }{d}}+{\frac{{a}^{2}}{4\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{5\,{a}^{2}}{8\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{15\,{a}^{2}}{8\,d\sin \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A] time = 1.05377, size = 140, normalized size = 1.21 \begin{align*} \frac{a^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - 17 \, a^{2} \log \left (\sin \left (d x + c\right ) - 1\right ) + 16 \, a^{2} \log \left (\sin \left (d x + c\right )\right ) - \frac{2 \,{\left (9 \, a^{2} \sin \left (d x + c\right )^{2} - 14 \, a^{2} \sin \left (d x + c\right ) + 4 \, a^{2}\right )}}{\sin \left (d x + c\right )^{3} - 2 \, \sin \left (d x + c\right )^{2} + \sin \left (d x + c\right )}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] time = 1.48133, size = 582, normalized size = 5.02 \begin{align*} \frac{18 \, a^{2} \cos \left (d x + c\right )^{2} + 28 \, a^{2} \sin \left (d x + c\right ) - 26 \, a^{2} + 16 \,{\left (2 \, a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2} -{\left (a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \sin \left (d x + c\right )\right ) +{\left (2 \, a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2} -{\left (a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 17 \,{\left (2 \, a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2} -{\left (a^{2} \cos \left (d x + c\right )^{2} - 2 \, a^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right )}{8 \,{\left (2 \, d \cos \left (d x + c\right )^{2} -{\left (d \cos \left (d x + c\right )^{2} - 2 \, d\right )} \sin \left (d x + c\right ) - 2 \, d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.24168, size = 155, normalized size = 1.34 \begin{align*} \frac{2 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) - 34 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) + 32 \, a^{2} \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) - \frac{16 \,{\left (2 \, a^{2} \sin \left (d x + c\right ) + a^{2}\right )}}{\sin \left (d x + c\right )} + \frac{51 \, a^{2} \sin \left (d x + c\right )^{2} - 122 \, a^{2} \sin \left (d x + c\right ) + 75 \, a^{2}}{{\left (\sin \left (d x + c\right ) - 1\right )}^{2}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]